Year 9 Computing: Autumn Assessment
Covers the law and your data, binary and hexadecimal, binary addition, units of storage, and how text, images and sound are represented. This is the first assessment that looks and feels like a GCSE paper.
Exam timer
Sit this to the clock. Working under time pressure is a separate skill from knowing the content, and it is the one most students never practise.
Instructions
- Answer every question.
- The marks tell you how many creditworthy points are wanted.
- No calculator is permitted.
- Read the command word before you start writing. State needs a fact. Describe needs a fact plus a detail. Explain needs a reason, usually a sentence containing the word because. Show your working in every conversion, because method marks are available even when the final answer is wrong.
Questions
Write a full answer to every question, then mark the whole paper at the end. Marking as you go teaches you far less.
- LInformation that can be used to identify a living person
Personal data is any information that can be used to identify a living person, such as a name together with an address, a date of birth, a photograph or an email address.
- LThe right to have inaccurate data corrected
- LThe right to have your data deleted, or to object to how it is used
You have the right to have data corrected if it is wrong, and the right to have your data deleted when there is no longer a good reason for the organisation to keep it. You can also object to your data being used for particular purposes, such as marketing.
- LShows a correct method, for example place values or repeated division
- LGives the answer 10101101
Writing the place values 128, 64, 32, 16, 8, 4, 2, 1 above the columns: 128 fits into 173 leaving 45, 64 does not fit, 32 fits leaving 13, 16 does not fit, 8 fits leaving 5, 4 fits leaving 1, 2 does not fit and 1 fits leaving 0. Reading the columns gives 10101101.
- LSplits the binary into two groups of four bits, 1101 and 0110
- LGives the answer D6
Split the eight bits into two groups of four, giving 1101 and 0110. The group 1101 is 8 + 4 + 1, which is 13, and 13 is written as D in hexadecimal. The group 0110 is 4 + 2, which is 6. So the answer is D6.
- LShows column addition with carries
- LGives the answer 10100001
- LAnswer is exactly 8 bits with no overflow
Adding from the right: 0 plus 1 is 1, 0 plus 0 is 0, 1 plus 1 is 0 carry 1, 1 plus 0 plus the carry is 0 carry 1, 0 plus 1 plus the carry is 0 carry 1, 1 plus 1 plus the carry is 1 carry 1, 1 plus 0 plus the carry is 0 carry 1, and 0 plus 0 plus the carry is 1. The answer is 10100001, which is 161 in denary, and 108 plus 53 does equal 161. It fits into eight bits, so there is no overflow.
- LThe result of the addition needs more bits than are available
- LA carry comes out of the leftmost column and is lost, so the stored answer is wrong
Overflow happens when the answer to an addition is too large to fit into the number of bits available. A carry is produced out of the leftmost column, but with only eight bits there is no ninth bit to hold it, so the carry is lost and the value that gets stored is not the correct answer.
- LMultiplies width by height by colour depth
- LConverts bits to bytes by dividing by 8
- LGives 480 KB
The number of pixels is 800 multiplied by 600, which is 480000. Each pixel needs 8 bits, so the image data is 480000 multiplied by 8, which is 3840000 bits. Dividing by 8 gives 480000 bytes, and dividing by 1000 gives 480 kilobytes.
- LColour depth is the number of bits used to store each pixel
- LEvery pixel in the image needs those extra bits, not just some of them
- LSo the total number of bits, and therefore the file size, goes up
Colour depth is the number of bits stored for each individual pixel, so it decides how many different colours a pixel can be. Increasing the colour depth adds bits to every single pixel in the image, not just to a few of them, so an image with a million pixels gains a million extra bits for each extra bit of colour depth. The total number of bits is width times height times colour depth, so raising the colour depth raises the file size in direct proportion.
- LA character set gives every character a unique binary code
- LThe computer stores the binary code, not the shape of the letter
- LSoftware uses the same character set to turn the code back into the letter when displaying it
A character set such as ASCII gives every character a unique number, and K is 75. The computer converts that number into binary, 01001011, and stores those eight bits. The shape of the letter is never stored: only the code is. When the character needs to be shown on screen, software looks the code up in the same character set and draws the matching symbol, which is why both machines have to agree on the character set for text to appear correctly.
- LOne hexadecimal digit represents exactly four bits
- LSo a value is written in a quarter of the characters
- LShorter values are easier to read and less likely to be mistyped or misread
Sixteen is two to the power of four, so one hexadecimal digit stands for exactly four bits and a whole byte becomes just two hexadecimal digits. A memory address written as eight ones and zeros is easy to lose your place in, and a single misread digit gives a completely different address. Written in hexadecimal the same value takes a quarter of the characters, so it is far quicker to read aloud, write down and compare, and far harder to get wrong.
- LMultiplies sample rate by bit depth
- LMultiplies by the number of seconds
- LDivides by 8 to get bytes
- LGives approximately 2.6 MB
The formula is sample rate times bit depth times seconds times channels. That gives 44100 times 16 times 30 times 1, which is 21168000 bits. Dividing by 8 gives 2646000 bytes, dividing by 1000 gives 2646 kilobytes, and dividing by 1000 again gives approximately 2.6 megabytes.
- LMore samples are taken every second
- LThe digital recording is a closer match to the original analogue sound
- LThe file size increases
- LMore processing power or bandwidth is needed to play or send it
Increasing the sample rate means the height of the wave is measured more often, so the steps of the digital version are narrower and the recording follows the shape of the original analogue wave far more closely, which improves the sound quality. The cost is size. Every extra sample is another set of bits to store, so the file grows in direct proportion to the sample rate, and a larger file takes longer to send over a network and needs more processing to play back.
- LHigher quality means more detail is kept, which matters for editing and for professional use
- LHigher quality files are much larger
- LLarge files fill storage quickly and cost more to store
- LLarge files take longer to send, upload or stream, especially on a slow connection
- LMost uses do not need the extra quality, as people cannot tell the difference on a phone screen or through earphones
- LReaches a reasoned conclusion, for example match the quality to the purpose
There is a real argument for high quality. Keeping more detail matters when a file is going to be edited, printed large or used professionally, because quality lost at the point of capture can never be recovered afterwards. Against that, quality costs size, and the cost is not small: doubling the sample rate or the colour depth roughly doubles the file. Large files fill storage quickly, which either means paying for more or deleting things, and they take much longer to upload, download or stream, which is a serious problem on a slow or metered connection. There is also the question of whether anybody notices. On a phone screen or through cheap earphones, most people genuinely cannot tell a very high quality file from a moderate one, so the extra bits buy nothing. The sensible conclusion is to match the quality to the purpose: capture and archive at high quality when the file will be edited or printed, and store or share a smaller version for everyday use.
This is an original paper written to match the structure, question style, command words and mark allocation of the real MskProd Year 9 Autumn assessment. It is not a past paper. Real past papers are the copyright of the exam board and cannot be republished here, so links to the official papers on the board's own site are provided on the exam papers page.